easy
0 views

Print 2N and 4N

Given an integer N, print the values of 2N and 4N.

Understand the Problem

Problem Statement

The program must accept an integer N as the input. The program must print 2N and 4N as the output.

For example, if N = 8, the output should be 16 and 32.

Constraints

  • Input Range: N can be any valid 32-bit signed integer (-2,147,483,648 ≤ N ≤ 2,147,483,647)
  • Output: Two integers printed on separate lines
  • Time Complexity: O(1) - constant time operations
  • Space Complexity: O(1) - no additional space required
  • Edge Cases: Handle negative numbers, zero, and maximum/minimum integer values

Examples

Example 1
Input
8
Output
16
32
Explanation

When N = 8, 2N = 8 × 2 = 16 and 4N = 8 × 4 = 32. The output shows these two values on separate lines.

Example 2
Input
5
Output
10
20
Explanation

When N = 5, 2N = 5 × 2 = 10 and 4N = 5 × 4 = 20. The output shows these two values on separate lines.

Example 3
Input
-3
Output
-6
-12
Explanation

The algorithm works with negative numbers too. When N = -3, 2N = -3 × 2 = -6 and 4N = -3 × 4 = -12.

Solution

#include <stdio.h>

int main() {
    int N;
    scanf("%d", &N);
    
    // Calculate and print 2N
    printf("%d\n", N * 2);
    
    // Calculate and print 4N
    printf("%d\n", N * 4);
    
    return 0;
}
Time:O(1) - Constant time operations (multiplication and print)</li>
Space:O(1) - Only uses one integer variable N
Approach:

This C solution:

  1. Declares an integer variable N
  2. Uses scanf() to read the input value
  3. Calculates 2N by multiplying N by 2 and prints it
  4. Calculates 4N by multiplying N by 4 and prints it
  5. Each result is printed on a separate line using \n (newline)

Visual Explanation

Loading diagram...
All Problems