JAVA – Package – EvenPrinter
Print all even numbers in a given range using a custom class
Understand the Problem
Problem Statement
The class Hello.java is given below.
import java.util.Scanner;
import com.letuscrack.util.EvenPrinter;
public class Hello {
public static void main(String[] args) {
Scanner scan = new Scanner(System.in);
int from = scan.nextInt();
int to = scan.nextInt();
EvenPrinter.printEvenRange(from, to);
}
}Write the code for the class EvenPrinter.java in the package com.letuscrack.util so that the program prints all even numbers in the given range (inclusive) separated by spaces.
Constraints
- 1 ≤ from ≤ to ≤ 1000
- Both from and to are integers
- The EvenPrinter class must be in the package com.letuscrack.util
- The method printEvenRange must be static and public
Examples
Example 1
Input
5 10Output
6 8 10Explanation
The range is 5 to 10. The even numbers in this range are 6, 8, and 10.
Example 2
Input
12 24Output
12 14 16 18 20 22 24Explanation
The range is 12 to 24. All even numbers from 12 to 24 inclusive are printed.
Example 3
Input
1 5Output
2 4Explanation
The range is 1 to 5. The even numbers in this range are 2 and 4.
Solution
#include <stdio.h>
// Simulating the EvenPrinter functionality in C
void printEvenRange(int from, int to) {
for (int i = from; i <= to; i++) {
if (i % 2 == 0) {
printf("%d ", i);
}
}
}
int main() {
int from, to;
scanf("%d %d", &from, &to);
printEvenRange(from, to);
return 0;
}Time:O(n) where n is the size of the range (to - from + 1)
Space:O(1) - only using a constant amount of extra space
Approach:
The C solution creates a function printEvenRange that iterates from from to to. For each number, it checks if it's divisible by 2 using the modulo operator. If the remainder is 0, the number is even and gets printed with a space separator.
Visual Explanation
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